Question

Smallest number which when decreased by 1 and increased by 3 is exactly divisable by 21,45,63,81,210

Answer 1

Answer:

5668

Step-by-step explanation:

21 = 3*7

45 = 3*3*5

63 = 3*3*7

81 = 3*3*3*3

210 = 2*3*5*7

=> lcm =  3*3*3*3*2*5*7 = 5670

let the smallest number be x

given x -1 +3 = 5670

ie, x +2 = 5670

=> x = 5670-2 = 5668