Question

Smallest number which when increased by 11 is exactly divisible by 15 and 130

Answer 1

Answer:

First ,find the L.C.M of 15 and 130 15 =3×5 130=2×5×13 so,l.c.m =2×3×5×13=390 Since,when the number increased by 11 is exactly divisible by 15and130 so,the required smallest number=390-11=379