smallest square number divisible by 8, 15, 20?
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Step-by-step explanation:
First, we have to find out the LCM of 8, 15 and 20 i.e. , 120.
We know that 120 is not a perfect square.
Therefore we need a number which when multiplied by 120, form a new number which is a perfect square.
prime factors of 120 = 2x2x2x5x3
Since, 2,5 and 3 are left unpaired,
Hence, we'll multiply 120 by 2,5 and 3 to get a number which is divisible by 8,15 and 20.
120 x 2 x 5 x 3 = 3600
Hence, 3600 is the required square number which is divisible by 8, 15 and 20. ANS.
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Answer:
3600
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