Smallest wavelength occurs for (a) Lyman series (b) Balmer series
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Answered by
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BY USING 1 / LEMDA = R ( 1/n1² - 1/n2²)
for smallest wavelength n1 and n2 are nearest orbital
and if we use n1 in ground state and n2 at ∞
then we get Lyman SERIES have smallest wavelength.......
HOPE IT HELPS AND IF IT'S HELPFUL THEN MAKE IT BRAINLIEST
for smallest wavelength n1 and n2 are nearest orbital
and if we use n1 in ground state and n2 at ∞
then we get Lyman SERIES have smallest wavelength.......
HOPE IT HELPS AND IF IT'S HELPFUL THEN MAKE IT BRAINLIEST
Answered by
4
Smallest wavelength occurs for Lyman series.
Option: (a)
Explanation:
- Lyman series is the series of wavelength of light that takes place when an electron jumps from the first orbital to the second orbital.
- Similarly Balmer series is that which takes place when an electron jumps from the first orbital to the third orbital.
- In hydrogen or hydrogen like ion, the wavelength is indirectly proportional to the orbital for which it is jumping.
- As a result the Lyman series will have its wavelength with shorter value than that of Balmer series.
Learn more about Lyman series
The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of balmer series for a hydrogen like ion. the atomic number z of hydrogen like ion is:
https://brainly.in/question/3572436
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