Math, asked by sami00740, 7 months ago

smallest whole number divisible by 720and 1575

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Answered by Vivek28r

Answer:

1575 = 720 * 2 + 135. 720 = 135 * 5 + 45. 135 = 45 * 3 + 0. Conclusion: Since r = 0, Therefore 45 is the HCF i.e the smallest whole number divisible by both 720 and 1575

Step-by-step explanation:

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smallest whole number divisible by 720and 1575​

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smallest whole number divisible by 720and 1575