Question

smipliy hard hard hard​

Answer 1

Answer:

If 'a'=1-√2,then find the value of (a-1/a)^3?

={[(1-√2)-(1/1-√2)]}³

={[(1-√2)²-1]/1-√2}³

={(1 -2√2+2-1)/(1-√2)}³

={(2-2√2)/(1-√2)}³

={2(1-√2)/(1-√2)}³,(by canceling (1-√2)

=(2)³

=8

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Answer 2

Answer:

a=1-√2

1/a=1/(1-√2)

or, 1/a=(1+√2)/(1-√2)(1+√2)

or, 1/a=(1+√2)/(1-2)

or, 1/a=-(1+√2)

∴, (a-1/a)³=[(1-√2)-{-(1+√2)}]³=(1-√2+1+√2)³=2³=8

Step-by-step explanation: 2 } ^

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