Math, asked by paridasharmistha2002, 8 months ago

Smita invested certain amount of money into schemes A and b which offer interest at the rate of 8% per annum and 9% per annum respectively. She received rupees 1860 as annual interest.however had she interchange the amount of investment in the two schemes she would have received rupees 20 more as annual interest. How much money did she invest in each scheme?​

Answers

Answered by SiddharthArya
4

Answer:

Let amount invested in A be Rs. x and in B be Rs. y.

As per the given statements, 0.08x+0.09y=1860.....(1)

And, 0.09x+0.08y=1880.....(2)

Multiplying equation (1) with 8 we get, 0.64x+0.72y=14880.....(3)

Multiplying equation (2) with 9 we get, 0.81x+0.72y=16920.....(4)

Subtracting equation (3) from (4), we get 0.17x=2040=>x=12000

Substituting x=12000 in the equation (1), we get 0.08(12000)+0.09y=1860⇒y=10000

Hence, amount invested A is Rs. 12000 and in B is Rs. 10000

Answered by rajmollah703
2

Answer:

She invested so ask the answer from Smita only you will get the correct answer.Pls mark me as brainliest

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