Question

Smith et al. [A-5] performed a retrospective analysis of data on 782 eligible patients admitted with

myocardial infarction to a 46-bed cardiac service facility. Of these patients, 248 (32 percent) reported

a past myocardial infarction. Use .32 as the population proportion. Suppose 50 subjects are chosen at

random from the population. What is the probability that over 40 percent would report previous

myocardial infarctions?​

Answer 1

Answer:

Answer to Smith et al. (A-5) performed a retrospective analysis of data on 782 eligible patients admitted with ... Of These Patients, 248 (32 Percent) Reported A Past Myocardial Infarction.

Explanation:

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Answer 2

0.11314

Explanation:

Binomial distribution X = Bin describes the number of subjects who would disclose past myocardial violations (50, 0.32). It is a type of probabilty distribution.

The result of 40 percent of 50 is 20.

As a result, we need to discover (P(Bin(50, 0.32) > 20). Because calculating this probability using the Binomial distribution is difficult and time-consuming, the central limit theorem and the normal distribution are applicable.