Smitha bought 3 bags of wheat flour. The ratio of the weight of Bag I to Bag II was 4 : 7. The ratio of the weight of Bag II to Bag III was 3 : 5. Bag II weighted 980 gm less than Bag III. Find the total weight of the 3 bags of wheat flour.
Answers
Answer:
MATHS
ABCD is a quadrilateral in which AD=BC and ∠ DAB=∠ CBA. Prove that ∠ABD =∠BAC.
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ANSWER
ABCD is a quadrilateral, where AD=BC and ∠DAB=∠CBA
In △ABD and △BAC,
⇒ AD=BC [ Given ]
⇒ ∠DAB=∠CBA [ Given ]
⇒ AB=BA [ Common side ]
∴ △ABD≅△BAC [ SAS Congruence rule ]
∴ ∠ABD=∠BAC [ CPCT ]
solution
Step-by-step explanation:
Given:-
Smitha bought 3 bags of wheat flour. The ratio of the weight of Bag I to Bag II was 4 : 7. The ratio of the weight of Bag II to Bag III was 3 : 5. Bag II weighted 980 gm less than Bag III.
To find:-
Find the total weight of the 3 bags of wheat flour.
Solution:-
No. of bags bought by Smitha =3
The ratio of the weight of bag Iand bag ll=4:7
It can be written as (4:7)×3=12:21.....(1)
The ratio of the weight of bag ll to bag lll=3:5
It can be written as (3:5)×7=21:35....(2)
From (1)&(2)
bag l: bag ll =12:21
bag ll: bag lll = 21:35
........................................................................
bag l: bag ll: bag lll= 12:21:35
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Then we have
The weight of bag l= 12 x
The weight of bag ll= 21x
The weight of bag lll= 35 x
now given that
Bag II weighted 980 gm less than Bag III
21x=35x-980gm
=>21x-35x=-980
=>-14x=-980
=>14x=980
=>x=980/14
=>x=70gm
12x=12×70=840 gm
21x=15×70=1470gm
35x=35×70=2450gm
Total weight of the 3 bags=840+1470+2450
=>4760 gm=4 kg 760 gm
Answer:-
Weight of the bag l=840 gm
Weight of the bag ll=1470gm=1kg 470gm
Weight of the bag lll=2450 mg=2 kg 450 gm
Total weight of the three bags =4760gm=4 kg 760gm