Smitha was travelling from Mumbai to Pune by car. Shehnaz was travelling from Mumbai to Pune by bus. Smitha covered a distance of 40 km in one hour while Shehnaz covered a distance of 80 km in two hours.
Who was travelling at a greater speed?
Smitha
2 Shehnaz
3 (Both were driving at the same speed.)
4 (Cannot be said as they did not cover the same distance.)
Answers
Answered by
1
Answer:
Both were driving at the same speed.)
Answered by
2
Answer:
distance = 80 km
time taken at original speed = 80/x
time taken at increased speed = 80/(x + 10)
80/(x + 10) = 80/x - 16/60 (It takes 16 min or 16/60 hrs less)
=> 5/(x + 10) = 5/x - 1/60
=> 5/(x + 10) = (300 - x)/60x
=> 300x = (300 - x)(x + 10) = 300x + 3000 - x^2 - 10x
=> x^2 +10x - 3000 = 0
=> x ^2 + 60x - 50x - 3000 = 0
=> x(x + 60) - 50(x + 60) = 0
=> (x - 50)(x + 60) = 0
=> x = 50 or -60. We’ll discard x = -60 as it is speed and should be positive.
The original speed of the bus is 50 km/h.
Explanation:
Let the original speed of the bus be x. The increased speed due to delay will be x + 10.
PLEASE MARK AS BRANLIST
Similar questions