Math, asked by parvinderyadav1497, 11 months ago

Smt. Desai sold shares of face value rupees 100 when the market value was rupees 50 and received rupees 4988.20. She paid brokerage 0.2% and GST on brokerage 18%, then how many shares did she sell ? Solve the word problem

Answers

Answered by amitnrw
10

Answer:

Smt. Desai sold 100 shares

Step-by-step explanation:

Let say Smt. Desai sold X shares

market value was rupees 50

so Selling Amount = 50X  Rs

Brokerage = (0.2/100) * 50X = 0.1X  Rs

GST on brokerage = (18/100) * 0.1X  = 0.018X

Brokerage including GST = 0.1X + 0.018X

= 0.118X

Amount Received = 50X - 0.118X

= 49.882X

49.882X  = 4988.20

=> X = 100

Smt. Desai sold 100 shares

Answered by 23saurabhkumar
4

Answer:

Number of shares sold = 100

Step-by-step explanation:

In the question,

The face value of shares sold by Smt. Desai = 100 Rs.

Market value of shares sold by Desai = 50 Rs.

Amount received = 4988.20 Rs.

Brokerage paid by her = 0.2 %

GST on brokerage = 18%

So,

Let us say she sold shares = x

So,

Selling Amount = 50x

So,

Brokerage = \frac{0.2}{100}\times 50x=0.1x

Now,

GST on brokerage = \frac{18}{100}\times 0.1x=0.018x

Therefore,

Brokerage with GST = 0.1x + 0.018x = 0.118x

Amount received = 50x - 0.118x = 49.882x

So,

Amount received = 4988.20

49.882x = 4988.20

x = 100

Therefore, we can say that the number of shares are equal to 100.

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