sn =0,a= 18,d=-2,n=?
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In AP , given that a=−2 and d=4
Given that the sum of first n terms in the series is S n =160
We know that the sum of first n terms in the series is S n = 2n
(2a+(n−1)d)⇒ 2n
(2a+(n−1)d)=160⇒ 2n
(−4+4(n−1))=160
⇒n(n−2)=80
⇒n=10,−8
Since n is positive integer , the value of n=1
I hope his different answer will help you .
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