Question

sn = 2n2+3n then find d

Answer 1

Answer:

bast would

Step-by-step explanation:

bast would ok

Answer 2

Answer:

sn=2n2+3nTn=sn−sn−1=2n2+3n−2(n−1)2−3(n−1)=2n2+3n−2n2+2n−2−3n+3=3n−2+n+3=4n+1T1=4+1=5T2=8+1=9d=−T1+T2d=9−5=4

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