Question

Sn=3n²-4n find the nth term

Answer 1

Answer.

$taking \: n = 1$

S1 =3(1)^2-4(1)

=-1

$taking \: n = 2$

S2 =3(2)^2-4(2)

=12-8

=4

$since |\: Sn-Sn-1= {n}^{th} \: term |$

S2-S1= 4-(-1)

=5

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Answer 2

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in Sn=3n²-4n let n=1

this means S1=3(1)²-4(1)

S1=3-4

S1=-1

But S1=a1

a1=-1

now let n=2 in Sn=3n²-4n

this means S2=3(2)²-4(2)

S2=3(4)-8

S2 = 12-8

S2 = 4

But S2=a1+a2

a1+a2= 4 But a1 =-1

a2=5

this means d1=a2-a1

d1=5-(-1)

d1=5+1

d1= 6

An=a+(n-1) d

An=-1+(n-1)(6)

An=-1+6n-6

An=6n-7