sn=8n-2 then find the a4 . it is in Ap.
is the answer is 22. is this correct or not
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GIVEN that
Sₙ = 8 n -2
so,
sum of first term will give us first term
i.e,
a₁=S₁
a₁ = 8 (1) -2
a₁=8-2
a₁=6 (= a,first term)
NOW ,
S₂ = a₁ + a₂
8 (2) - 2 = 6 + a₂
14 = 6 + a₂
a₂ = 14-6
a₂ = 8
NOW,
S₃= a₁ + a₂ + a₃
8 ( 3) -2 = 6 + 8 + a₃
a₃ = 22 - 14
a₃ = 8
now we can easily see in a₁ , a₂ , a₃ that the common difference is not same hence,eqn that Sₙ = 8 n -1 is not correct to find the sum of n terms of AP and a₁ , a₂ , a₃ does not form an AP.
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