Sn denotes the sum of AP whose common difference is d show that d= Sn-2Sn-1+Sn-2
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Answered by
65
Answer:
Here,
Tn = Sn-Sn-1
Tn-1 = Sn-1-Sn-2
Sn-2(Sn-1)+Sn-2 = Sn-Sn-1-Sn-1+Sn-2
= (Sn-Sn-1)-(Sn-1-Sn-2)
= Tn-Tn-1
= d
Answered by
58
answer of above question is following
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