Question

SN is equal to 3n square - 4n find a and d​

Answer 1

Answer:Let the sum of first n terms of the A.P.=Sn

 Given: Sn = 3n2 – 4n    ...(i)

Now,

Replacing n by (n –1) in (i), we get,

 Sn – 1 = 3(n – 1)2 – 4(n – 1)  

nth term of the A.P. an = Sn – Sn – 1

 ∴ an = (3n2 – 4n) – [3(n – 1)2 – 4(n – 1)]

⇒ an = 3 [ n2 – (n – 1)2] – 4 [n – (n – 1)]

⇒ an = 3 (n2 – n2 + 2n – 1) – 4 (n – n + 1)

⇒ an = 3(2n –1) – 4

⇒ an = 6n – 3 – 4

⇒ an= 6n – 7

Thus, the nth term of the A.P = 6n – 7.

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