sn=n^2+n, then find the 5th term of the ap
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Step-by-step explanation:
Sn=n^2+n
n/2(2a+(n-1)d)=n^2+n
2a+(n-1)d=2(n^2+n)/n
2a+(n-1)d=2n(n+1)/n
2a+(n-1)d=2n+2
Let,
n=1
=2a+(1-1)d=2(1)+2
=2a+0=4
2a=4
a=2
Let,
n=2
=2a+(2-1)d=2(2)+2
=4+d=6
=d=6-4
=d=2
a5= a+4d
=2+4(2)
=10
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