Sn = n(n+1)/2, find t, and check it is A.P. or not.
Answers
Answered by
2
Answer:
Sn = (n)(n + 1)/2
» S (n + 1) = (n + 1) (n + 2)/2
Now, t (n + 1) = (n + 1)/2 [ n + 2 - n]
» t (n + 1) = n + 1
» tn = n
d = t (n + 1) - tn
» d = n + 1 - n = 1
» d = 1 = constant
Therefore, it forms an A.P.
Similar questions