Sn=n×n (n+1).Hence the 2nd term of AP will be ___
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Answered by
1
By finding An for n=3
S3=3*3(3+1). S2 = 2*2(2+1)
=3*3(4). = 2*2(3)
= 15 = 8
tn =Sn -Sn-1........formula
For n=3
t2= S3 -S3-1
= S3-S2
= 15-8
= 7
The second term is 7
S3=3*3(3+1). S2 = 2*2(2+1)
=3*3(4). = 2*2(3)
= 15 = 8
tn =Sn -Sn-1........formula
For n=3
t2= S3 -S3-1
= S3-S2
= 15-8
= 7
The second term is 7
Answered by
1
Answer:
Sn = n*n(n+1)
so we take n = 1
S1= 1*1(1+1)
S1= 1(2)
S1=2
a=2
now we take
S2 = 2*2(2+1)
S2= 4(3)
S2= 12
WE KNOW THAT S2-S1 =a2
so
12-2 =a2
10= a2
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