Math, asked by akshatrajesh35, 6 months ago

Sn=nC0nC1+nC1nC2+nC2nC3+......+nCn-1nCn then for very large value of n(n approaches infinity.

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Answered by Anonymous

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Answer:

Sn=nC0*nC1+nC1*nC2+nC2*nC3+......+nCn-1*nCn then for very large value of n(n approaches infinity.Step-by-step explanation:

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