Question

sn2+ is more common than sn4+ explain

Answer 1

The most common oxidation states of the group are +2 and +4. ... And for this reason,Sn4+ is slightly more stablethan Sn2+ though tin does form compounds in both the oxidation states.

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Answer 2

Answer: This happens because of inert pair effect.

Explanation:

Tin is the 50th element of the periodic table having electronic configuration of $[Kr]4d^{10}5s^25p^2$

Tin has 4 electrons in the valence shell, two in the s-sub shell and two in the p-sub shell. It can show positive oxidation states of +2 (due to participation of only p-electrons) and +4 (due to the participation of s and p-electrons).

Tin has d- and f-electrons in the inner shell and thus shields the s-electrons of the valence shell more effectively than the p-electrons.

Thus, the tendency of participation of s-electrons in the bond formation decreases and that of p-electrons increase. This is called as inert pair effect.

Hence, $Sn^{2+}$ is more common than $Sn^{4+}$