sn4+ +2e-=sn2+ is is reduction or oxidation
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↪Actually welcome to the concept of the Redox Reactions ...
↪Since here the given element is Stroncium ...
↪↪Sn^4+ + 2e- = Sn^2+
↪Thus Here we can clearly see that the Oxidation number or the oxidation state of the Tin is decreasing, thux indicating it is a ⭐REDUCTION REACTION⭐ ...
↪So eventually when there is decrese in oxidation number , there is gain of electron and thus it is a Reduction Reaction
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