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When roots are given, equation in quadratic form
x2−(α+β)x+αβ=0
Here roots are (2α+3β) and (3α+2β)
∴x2−(2α+3β+3α+2β)x+(2α+3β)(3α+2β)=0
x2−5(α+β)x+6α2+4αβ+4αβ+6β2=0
f(x)=2x2−5x+7
α+β=25, αβ=27
∴α2+β2=(α+β)2−2αβ
=425−7=4−3
x2−5(25)x+6(−43)+13×
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