Question

Sneha is thrice old as Shyam. 6 years
ago her age was four times Shyam's
age. Find their present ages.​

Answer 1

Step-by-step explanation:

Step-by-step explanation:Correct option is

Step-by-step explanation:Correct option isB

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 years

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is x

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is xSo according to 1

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is xSo according to 1 st

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is xSo according to 1 st condition

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is xSo according to 1 st condition⇒4(x−5)=y−5

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is xSo according to 1 st condition⇒4(x−5)=y−5⇒4x−20=y−5

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is xSo according to 1 st condition⇒4(x−5)=y−5⇒4x−20=y−5⇒5+y=2(x+5)

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is xSo according to 1 st condition⇒4(x−5)=y−5⇒4x−20=y−5⇒5+y=2(x+5)∴5+(4x−15)=2(x+5)

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is xSo according to 1 st condition⇒4(x−5)=y−5⇒4x−20=y−5⇒5+y=2(x+5)∴5+(4x−15)=2(x+5)∴x=10

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is xSo according to 1 st condition⇒4(x−5)=y−5⇒4x−20=y−5⇒5+y=2(x+5)∴5+(4x−15)=2(x+5)∴x=10now from eq. (i) we get,

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is xSo according to 1 st condition⇒4(x−5)=y−5⇒4x−20=y−5⇒5+y=2(x+5)∴5+(4x−15)=2(x+5)∴x=10now from eq. (i) we get,⇒y=25

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is xSo according to 1 st condition⇒4(x−5)=y−5⇒4x−20=y−5⇒5+y=2(x+5)∴5+(4x−15)=2(x+5)∴x=10now from eq. (i) we get,⇒y=25∴ y=25 and x=10

Answer 2

Answer:

Step-by-step explanation:Correct option isBPresent age of A=25 years and that of B=10 yearsLet the present age of A be y and of B is xSo according to 1 st condition⇒4(x−5)=y−5⇒4x−20=y−5⇒5+y=2(x+5)∴5+(4x−15)=2(x+5)∴x=10now from eq. (i) we get,⇒y=25∴ y=25 and x=10.