Question

Sneha is twice Neha's age. 7 years ago, Sneha was three times Neha's age.

Find their ages.​

Answer 1

Answer:

Let Nisha was x, 4 years back and so Neha was 8x, 4 years back.

 

After 4 years from today i. e. 8 years from the past, both Nisha and Neha would be x+8 and 8x+8 respectively. From the given data

 

2*(x+8) = 8x+8

 

Therefore, x = 4/3 years i. e Nisha was 4/3 years or 16 months old 4 years back and Neha was 32/3 years or 128 month old.

 

When we add 4 to both 4/3 and 32/3, we will get their current age.

 

4/3 + 4 = 16/3 years i. e. 64 Months for Nisha.

 

32/3 + 4 = 44/3 years i. e. 176 Months for Neha.

 

Today, Neha is 44/3 Years and Nisha is 16/3 Years.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

let the present age of sneha and Neha be X and y respectivly

presently,

y = 2x;

7years ago,

3(x-7) = y-7;

3x-21 = y-7

or 3x-y= 14;

3x-2x=14 or

X = 14,

or y =28,

therefore age of sneha is 28 and of Neha is 14