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tn= 3n-2
t1 =3(1)-2
=3-2
t1=1
similarly for 2nd term
t2=3(2)-2
=6-2
t2=4
so d= t2-t1
= 4-1
d= 3
t1 =3(1)-2
=3-2
t1=1
similarly for 2nd term
t2=3(2)-2
=6-2
t2=4
so d= t2-t1
= 4-1
d= 3
shiv8112:
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3 is the answer
explain
I explained see the answer
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