So
compound C = 4o7. H = 6.3%
0= 53-3.
molecular mass = 60
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Explanation:
A compound contains 40% carbon, 6.7% hydrogen, and 53.3%oxygen.
100 g of the compound will contain 40 g C, 6.7 g H and 53.3 g O.
The atomic masses of C, H and O are 12 g/mol, 1 g/mol and 16 g/mol respectively.
The number of moles of C=
12 g
40 g
=3.33 mol
The number of moles of H=
1 g
6.7 g
=6.7 mol.
The number of moles of O=
16 g
53.3 g
=3.33 mol.
The mole ratio C:H:O=3.33:6.7:3.33=1:2:1
The empirical formula of compound is CH
2
O.
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