Question

So guys,
find the value of
x - 2y + 3z
when
x = 2a²-a³+3a+4
y= 2a³-3a²+2-2a
z= a⁴+3a³-6-5a²​

Answer 1

Answer:

Given,

x−2y+3z=11−−−−−(1)

3x+y−z=2−−−−−−(2)

5x+3y+2z=3−−−−−(3)

Multiplying (1) with 3 and then solving with (2),we get,

10z−7y=31−−−−−(4)

Multiplying (1) with 5 and then solving with (3),we get,

z−y=4−−−−−−(5)

Now,multiplying (5) with 7 and then solving with (4),we get,

=>z=1

Putting the value of z in (5),

y=−3

putting the value of z and y in (1),

x=2.

I hope it will help you