Question

so I'm reposting it. someone please help me with 26 and ii part of 27 question.. {and 8 from my previous question.} my teacher will surely kill me I didn't show it to him tomorrow.. [classes still going on -_-*] ​

Answer 1

Step-by-step explanation:

$x = \dfrac{1}{2 - \dfrac{1}{2 - \dfrac{1}{2 - x} } } \\ x = \dfrac{1}{2 - \dfrac{1}{ \dfrac{4 - 2x - 1}{2 - x} } } \\ x = \dfrac{1}{ 2 - \dfrac{2 - x}{3 - 2x} } \\ x = \dfrac{1}{ \dfrac{6 - 4x - 2 + x}{3 - 2x} } \\ x = \dfrac{3 - 2x}{4 - 3x} \\ x(4 - 3x) = 3 - 2x \\ 4x - 3 {x}^{2} = 3 - 2x \\ - 3 {x}^{2} + 6x - 3 = 0 \\ {x}^{2} - 2x + 1 = 0 \\ {(x - 1)}^{2} = 0 \\ x - 1 = 0 \\ x = 1$