Question

So,I Need Answer For This​

Answer 1

Answer

Correct option is

C

4z(4z+3)

Let us first factorize (32z

2

−18) as follows:

32z

2

−18

=2(16z

2

−9)

=2[(4z)

2

−3

2

)]

=2(4z+3)(4z−3)(∵a

2

−b

2

=(a+b)(a−b))

Since we have to divide

13z

2

(4z−3)

26z

3

(32z

2

−18)

, therefore, we will divide

13z

2

(4z−3)

52z

3

(4z+3)(4z−3)

as shown below:

13z

2

(4z−3)

52z

3

(4z+3)(4z−3)

=

13

52

×

z

2

z

3

×

(4z−3)

(4z+3)(4z−3)

=

13

2×2×13

×

1

z

3

×z

−2

×(4z+3)

=4×z

3−2

×(4z+3)(∵a

x

+a

y

=a

x+y

)

=4z(4z+3)

Hence,

13z

2

(4z−3)

26z

3

(32z

2

−18)

=4z(4z+3).

Answer 2

Answer:

$\huge\color{pink}\mathfrak{Asnwer}$

Step-by-step explanation:

${26z}^{3} ( {32z}^{2} - 18) \div {13z}^{2} (4z - 3) \\ 2z(32 {z}^{2} - 18) \div (4z - 3) \\ 64 {z}^{3} - 18z \div 4z - 3 \\ 16 {z}^{2} + 12z \: is \: the \: quotient \\ remainder \: = 18z$

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