Question

so that 7^n can not end with the digit 0 for any natural number N​

Answer 1

Answer:

Step-by-step explanation:

See the cyclicity that 7^0=1,7^1=7,7^2=49,7^3=343,7^4=2401

We can see the last digit 1 has got repeated so there's no chance for 0 to end

Answer 2

Answer:

7^1=7

7^2=49

7^3=343

7^4=2401.....

so 7^n can not end with 0 for any natural number