so that 8^2,12^n and 30^n end with the digit 0
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as 8^2=64
we need 12^n such that it has 6 on the unit place. I.e. 12^4=(144)^2=19636
now 19636+64=19700
for 30^n you can choose anything >0
we need 12^n such that it has 6 on the unit place. I.e. 12^4=(144)^2=19636
now 19636+64=19700
for 30^n you can choose anything >0
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