Question

so that a charge Q be divided equally into two parts to have maximum force repulsion between them​

Answer 1

Answer:

its too deifficult question

Answer 2

 show that a charge Q be divided equally into  q=Q/2

1).  Force between two charged particles is given by

 F =   (K*Q1*Q2)/(R*R)    where K is Force constant  Q1 is first charge , Q2 is second charge , R is distance between them

2).  So for given question R is constant

so let us assume C=K/(R*R)  where C is another constant

3).  Let us assume the charge Q is divided into two parts one having a charge q then the other one will have charge (Q-q)

4). putting these things in the force equation  we get

    F = C*q*(Q-q)

5). for maximum we differentiate this with respect to q and equate to zero

we get  

0 = C*(Q-q)   -  C*q      Dividing by C on both sides and cancelling it

implies   (Q-q) - q   = 0

Q -2q = 0

Q/2 = q

there for maximum force of repulsion charge must be divided into equal parts