So the remainder obtained on dividing q(7) by 2t+ 1 is 0.
21 + 1.
EXERCISE 2.3
1. Find the remainder when x3 + 3x2 + 3x + 1 is divided by
1
(V) 5+2
(1) x+1
(ii) x-
(iv) x +7
2
2. Find the remainder when x3 - ax2 + 6x - a is divided by x-a.
3. Check whether 7 + 3x is a factor of 3x3 + 7x.
So, 21 + 1 is a factor of the given polynomial gt), that is g(t) is a multiple
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