Question

So um... I forgot the lecture in class... please help... -_-






Oh btw much points!

Answer 1

Note......if we set the "y's" equal, then we have

 

4x - 2   = 5

 

Then.......the resulting x value for the solution of this equation is the x coordinate for the intersection point.......so.........add 2 to each side

 

4x  = 7     divide both sides by 4

 

x = 7/4      so........ (3, 6)  cannot possibly be the intersection point

 

And as  xvxvxv pointed out,  the intersection point is actually (7/4, 5)  or ( 1.75, 5)

 



 

 

Answer 2

Answer:

(2,6)

Step-by-step explanation:

Given Equation are:

y = 4x - 2   ---- (i)

y = (1/2)x + 5   ---- (ii)

Given that it intersects at (3,6).

Substitute x = 3 and y = 6 in both the equations and check it.

(i)

y = 4(3) - 2.

6 = 12 - 2

6 ≠ 10.

(ii)

6 = (1/2) * 3 + 5

6 = (3/2) + 5

6 = 13/2

6 ≠ 6.5.

∴ She is not correct, because the point does not make both equations true.

Solution:

The solution will be the coordinate (x,y) such that y₁ = y₂ and x₁ = x₂.

⇒ 4x - 2 = (1/2)x + 5

⇒ 4x - (x/2) = 5 + 2

⇒ 7x/2 = 7

⇒ 7x = 14

⇒ x = 2.

Now,

Substitute x = 2 in (i), we get

⇒ y = 4x - 2

⇒ y = 4(2) - 2

⇒ y = 8 - 2

⇒ y = 6.

∴ Finally, that means out solution coordinates is (2,6).

Hope this helps!