French, asked by DarThWadEr, 9 months ago

So x + y = 8, et XY = 15 trouvez x ^ 2 + y ^ 2​

Answers

Answered by Anonymous
16

x+y = 8

xy=15

(x+y)^2=8^2

x^2+y^2+2xy = 64

x^2+y^2+2*15 = 64(since xy=15)

x^2+y^2 = 64-30

x^2+y^2 = 34

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34 is answer

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Answered by Anonymous
0

x+y = 8

xy=15

(x+y)^2=8^2

x^2+y^2+2xy = 64

x^2+y^2+2*15 = 64(since xy=15)

x^2+y^2 = 64-30

x^2+y^2 = 34

34 is answer

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