Chemistry, asked by rohinichilke14, 10 months ago

So2+2H2s=2H2o+3s oxsidised

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Answered by premkumaryadav146503
1

Answer:

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Answered by yajat1810
1

in this rxn the sulphur atom is both reduced and oxidised as in H2S the O.N. of S = -2

and in SO2 the O.N. = +4

the O.N. of S in product is 0

so the Sulphur is both reduced and oxidised

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