Math, asked by andrajayanth4098, 10 months ago

Social welfare association deci des to supply drinking water to the flood affected people the drinking water is in the shape of a cylinder with hemispherical end .the whole length of the tanker is 4.2 meters and diameter of base of the cylinder and 2 hemispheres are each 1.2 metres if they distribute drinking water to 60 people in a container each is in the shape of cylinder of radius 21cm and height 50cm find the quantity of water left in the tanker after distribution in litre

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Answered by monishss143
1

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Answered by psupriya789
0

Step 1:

The length of the water tank = 4.2 m

The diameter of the base of the cylinder and the two hemispherical ends,

d = 1.2 m

So, the radius, r = d/2 = 1.2/2 = 0.6 m

∴ The length of the cylindrical portion of the tank, h = 4.2 - 1.2 = 3 m

Now,

The volume of the cylindrical portion is,

= πr²h

= × 0.6² × 3

= 3.39 m³

and

The volume of the 2 hemispherical ends is,

= 2 × [ πr³]

= × × 0.6³

= 0.905 m³

∴ The volume of the drinking water tank is given by,

= [ volume of the cylindrical portion] + [volume of the 2 hemispherical ends]

= 3.39 m³ + 0.905 m³

= 4.295 m³

Step 2:

The dimension of the small cylindrical containers:

Radius, r = 21 cm = 0.21 m

Height, h = 50 cm = 0.5 m

The no. of people to whom the drinking water was distributed in cylindrical containers = 60

∴ The volume of water distributed to 60 people is given by,

= 60 * [Volume of the cylindrical containers]

= 60 * [πr²h]

= 60 * (22/7) * 0.21² * 0.5

= 4.158 m³

Step 3:

Therefore,

The quantity of water left in the tanker after the distribution is given by,

= [volume of the drinking water tank] – [volume of water distributed to 60 people]

= 4.295 m³ - 4.158 m³

= 0.137 m³

∵ 1 m³ = 1000 litres

= 137 litres

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