Social welfare association decide to supply drinking water for the flood affected people the drinking water is filled in the water tank which is in the shape of a cylinder with hemispherical shown in the figure the hole in the tank is 4.2 metre and the diameter of the base of the cylinder and two hemispheres are each 1.2 metre if there distribute drinking water to 60 people in a container reach in shape of a cylinder of radius 21 cm and height 15 cm find the quantity of water left the tanker of a distribution in litre
Answers
Answer:
Step-by-step explanation:
Assuming what you meant by hole of 4.2m as the height of cylinder
Quantity of water left =
Volume of tank - volume of 60 cylinders
= π×60×60×420 - 60×π×21×21×15 + 4/3×π×21^3
= 4752000 - 1247400 + 38808 cm^3
= 3504600 + 38808 cm^3
3543408 cm^3 = 3543.408 litre
Answer:
Quantity of water left in the tanker = 1,499 litters
Step-by-step explanation:
The quantity of water left in the tanker after distribution = Total quantity - Distributed quantity
Total quantity = Volume of the tanker
Volume of the cylinder of 4.2 m length and 1.2 m of a diameter.
Volume of cylinder = π r² L
(given L = 4.2m and diameter = 1.2m)
Substituting, we get Volume (cylinder) = 22/7 * 0.6 * 0.6 * 4.2 = 4.752 m³
Volume of 2 hemispheres at the end = 2* 2πr³/3 = 4 * 22/7 * (0.6)³ / 3 = 792 / 875 m³
Volume of tanker = 4.752 + 792/875 = 5.657 m³
Distributed quantity = 60 times the volume of a cylinder of radius 21 cm and height is 50 cm
= 60 * πr²L
= 60 * 22/6 * 21² * 50
= 4,158,000 cm³
= 4.158 m³
The quantity of water left in the tanker after distribution = 198/35 - 4.158 = 1.499 m³
1 m³= 1,000 litter
So quantity of water left in the tanker after distribution = 1.499 * 1000 = 1499 litters
hope it helps u
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