Math, asked by manjumanjula0101, 11 months ago

social welfare Association decided to supply drinking water for the flood affected people the drinking water is filled in a water tanker which is in the shape of a cylinder with hemispherical and as shown in the figure the whole length of the tanker is 4.2 metre and the diameter of the base cylinder and two hemisphere are each 1.2 metre if they distribute drinking water 60 people in a container each is the shape of the cylinder of radius 21 cm and height 50 cm find the quantity of water left in the tanker after distribution in litre

Answers

Answered by kishoreddy3
15

Answer:

Step-by-step explanation:

Attachments:
Answered by amitnrw
1

Given :  A water container cylindrical  with two hemispherical ends . to distribute Drinking water for 6o people

To find : Water left in Tank

Solution:

Length of Tanker is 4.2 m

Radius of base of cylinder = hemisphere = 1.2/2 = 0.6 m

Length of each hemisphere = 0.6 m

Length of cylindrical part = 4.2 - 0.6 - 0.6 = 3 m

Volume of Cylinder = π r²h

= π (0.6)² * 3 m³

Volume of two hemisphere = 2 * (2/3)π r³

= (4/3) π (0.6)³

= 0.8 π (0.6)²  m³

Total Volume =  3.8 π (0.6)²  m³

= 1.368 π  m³

Volume of one container = π (21/100)² * (50/100) m³

= π (.21)² / 2   m³

Volume of 60 container = 60 *  π (.21)² / 2   m³

= 30   π (.21)²    m³

= 1.323 π   m³

Water left in Tank =  1.368 π  -  1.323 π  = 0.045 π   m³

= 0.045 π   m³

= 0.141  m³

1 m³ = 1000 litre

=> 0.141  m³  = 141 Litre

141 litre water left in Tank

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