social welfare Association decided to supply drinking water for a flood affected people the drinking water is filled in the water tanks which is in the shape of cylinder with hemispherical ends as shown in the figure the overall length of the tanker is 4.2 metre and diameter of base of the cylinder 12 hemispheres are each 1.2 metre if the distribute drinking water to 60 peoples in a container each is in the shape of a cylinder of radius 21 cm and 8 cm find the quantity of water left in the tanker of the distributed in litre
Answers
Answer:
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Step 1:
The length of the water tank = 4.2 m
The diameter of the base of the cylinder and the two hemispherical ends,
d = 1.2 m
So, the radius, r = d/2 = 1.2/2 = 0.6 m
∴ The length of the cylindrical portion of the tank, h = 4.2 - 1.2 = 3 m
Now,
The volume of the cylindrical portion is,
= πr²h
= × 0.6² × 3
= 3.39 m³
and
The volume of the 2 hemispherical ends is,
= 2 × [ πr³]
= × × 0.6³
= 0.905 m³
∴ The volume of the drinking water tank is given by,
= [ volume of the cylindrical portion] + [volume of the 2 hemispherical ends]
= 3.39 m³ + 0.905 m³
= 4.295 m³
Step 2:
The dimension of the small cylindrical containers:
Radius, r = 21 cm = 0.21 m
Height, h = 50 cm = 0.5 m
The no. of people to whom the drinking water was distributed in cylindrical containers = 60
∴ The volume of water distributed to 60 people is given by,
= 60 * [Volume of the cylindrical containers]
= 60 * [πr²h]
= 60 * (22/7) * 0.21² * 0.5
= 4.158 m³
Step 3:
Therefore,
The quantity of water left in the tanker after the distribution is given by,
= [volume of the drinking water tank] – [volume of water distributed to 60 people]
= 4.295 m³ - 4.158 m³
= 0.137 m³
∵ 1 m³ = 1000 litres
= 137 litres