Sodium borohydride on reaction with I2 gives a compound 'A' in which
hybridisation state of boron is 'B'. 'A' and 'B' respectively are
1) B2H6, sp2
2) B2H6, sp3
3) Bl3, sp2
4) Bl3, sp3
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1
Answer:
2
Explanation:
B2H6
sp3
(diborane)
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