Question

Sodium carbonate reacts with ethanoic acid to form sodium ethanoate, carbon
dioxide and water. In an experiment, 5.3 g of sodium carbonate reacted with 6 g
of ethanoic acid to form 8.2 g of sodium ethanoate, 2.2 g of carbon dioxide and
0.9 g of water. Show that this data verifies the law of conservation of mass.

Answer 1

Explanation:

ANSWER

According to the question,

Na

2

CO

3

+CH

3

COOH→CO

2

+H

2

O+CH

3

COONa

Mass of reactants =5.3+6=11.3 gm

Mass of products =2.2+0.9+8.2=11.3 gm

This shows, that during a chemical reaction, the mass of reactant = mass of the product.

Hence, it shows the law of conservation of mass.

Answer 2

Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water

Solution :

Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water

5.3g 6g 8.2g 2.2g 0.9g

As per the law of conservation of mass, the total mass of reactants must be equal to the total mass of products

As per the above reaction, LHS = RHS i.e., 5.3g + 6g = 2.2g + 0.9 g + 8.2 g = 11.3 g