sodium carbonate reacts with ethanoic acid to form sodium ethanoate, carbon dioxide and water. In this experiment 5.3g of sodium carbonate reacts with 6g of ethanoic acid to form 8.2 g of sodium ethanoate 2.2 g of carbon dioxide and 0.9g of water. Show that this data verify the law of conservation of mass
Answers
Total mass of reactants = mass of sodium carbonate + mass of ethanoic acid
= 5.3 g + 6 g= 11.3 g
Total mass of products = mass of sodium ethanoate + carbon dioxide + water
= 8.2 g + 2.2 g + 0.9 g = 11.3 g
Thus, the mass of reactants is equal to the mass of products, therefore the observations are in agreement with the law of conservation of mass.
⇒ Mass of reactants = Mass of sodium carbonate + Mass of ethanoic adid = 5.3 + 6.0 = 11.3 g
⇒ Mass of products = Mass of sodium ethanoate + Mass of carbon dioxide + Mass of water = 8.2 + 2.2 + 0.9 = 11.3 g
⇒ Since, the mass of reactants is equal to the mass of products, Therefore, the observation made is in agreement with the law of conservation of mass. That mass can neither be created or destroy during Chemical reaction.