Sodium crystallizes in bcc arrangement with the interfacial seperation
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Here,Z=2(bcc)al
a=53×2=106pm=(106×10^-10)cm
M=58.5 g/mol.
D=MZ/N a^3=58.5×2/6.022×10^23×(106×10^-10)
=117/0.72=162.5 g/cc..
a=53×2=106pm=(106×10^-10)cm
M=58.5 g/mol.
D=MZ/N a^3=58.5×2/6.022×10^23×(106×10^-10)
=117/0.72=162.5 g/cc..
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