sodium crystallizes in BCC unit cell what is the approximate number of unit cells in 4.6 gram of sodium
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Answered by
3
Hi!
Here is the answer to your question.
Let the tens digit be x and the ones digit be y.
x + y = 9 … (1)
Original number = 10x + y
Reverse number = 10y + x
Given, Reverse number = Original number + 27
∴10y + x = 10x + y + 27
⇒ 9y – 9x = 27
⇒ y – x = 3 … (2)
Adding (1) and (2),
⇒ y = 6
When y = 6,
x + 6 = 9 (Using (1))
x = 9 – 6 = 3
∴ Original number = 10x + y = 10 × 3 + 6 = 30 + 6 = 36
Hope it help....
Plss mark me as brilliant
Here is the answer to your question.
Let the tens digit be x and the ones digit be y.
x + y = 9 … (1)
Original number = 10x + y
Reverse number = 10y + x
Given, Reverse number = Original number + 27
∴10y + x = 10x + y + 27
⇒ 9y – 9x = 27
⇒ y – x = 3 … (2)
Adding (1) and (2),
⇒ y = 6
When y = 6,
x + 6 = 9 (Using (1))
x = 9 – 6 = 3
∴ Original number = 10x + y = 10 × 3 + 6 = 30 + 6 = 36
Hope it help....
Plss mark me as brilliant
Answered by
7
Atomic mass of sodium = 23 g
This means, 23 g of sodium contains 6.023 x 1023 atoms
Now, number of atoms in a unit cell of bcc structure = 2
Therefore,
the number of unit cells which contain 1.20x10 23 =1.20x10 23
/2 atoms
= 6 x 1022 unit cells.
This means, 23 g of sodium contains 6.023 x 1023 atoms
Now, number of atoms in a unit cell of bcc structure = 2
Therefore,
the number of unit cells which contain 1.20x10 23 =1.20x10 23
/2 atoms
= 6 x 1022 unit cells.
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