Question

sodium + Dil sulphuric acid=? magnesium + water=? zinc + sodium hydroxide=?​

Answer 1

Explanation:

Reaction of sodium metal with dilute acid: Sodium metal gives sodium chloride and hydrogen gas when it reacts with dilute hydrochloric acid.

2Na + 2HCl ⇨ 2NaCl + H2

Magnesium burns in steam to produce white magnesium oxide and hydrogen gas. Very clean magnesium ribbon has a very slight reaction with cold water. After several minutes, some bubbles of hydrogen form on its surface, and the coil of magnesium ribbon usually floats to the surface.

1 mg

Zinc react with excess sodium hydroxide to form sodium zincate(Na2ZnO2) along with hydrogen gas. When Zn is boiled with NaOH solution than H2 gas evolves, forming sodium zincate. Zinc reacts with sodium hydroxide to form sodium zincate.

Answer 2

Answer:

sodium + Dil sulphuric acid

= H2SO4 + NA2CO3 ==> NA2SO4 + H2O + CO2

magnesium + water

= Mg (s) + 2H 2 O(g) -> Mg(OH) 2 (aq) + H 2 (g)

zinc + sodium hydroxide

= Zn + 2NaOH Na 2 ZnO 2 + H 2

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