sodium has a bcc structure with nearest neighbour distance 365.9 pm. calculate its density
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As we have bcc structure, nearest neighbour distance (d) is related to the edge length (a) as follows :
d =√3a/2
or a =2d/√3
= (2×365.9) ÷ 1.732
= 422.5 × 10^(-10) cm
for bcc structure , z = 2
for sodium M = 23 g/mol
Density ρ = (z × M) ÷ (a^3 × N(a))
= [2 × 23] ÷ [ { 422.5 × 10^(-10) }^3 × 6.02 × 10^23
Density = 1.51 g/cm3
d =√3a/2
or a =2d/√3
= (2×365.9) ÷ 1.732
= 422.5 × 10^(-10) cm
for bcc structure , z = 2
for sodium M = 23 g/mol
Density ρ = (z × M) ÷ (a^3 × N(a))
= [2 × 23] ÷ [ { 422.5 × 10^(-10) }^3 × 6.02 × 10^23
Density = 1.51 g/cm3
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