SODIUM HYDROXIDE is formed near the cathode. why?
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During electrolysis of brine(aq. NaCl), NaCl and water are present as electrolyte.
Na+ (from NaCl) and H+(from water) tends to move to negative terminal (i.e cathode) while Cl- (from NaCl) and OH-(from water) tends to move to positive terminal(i.e anode).
Now only one from Na+ and H+ at cathode will get reduce which has higher standard reduction potential.
hope it helped
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